Acids, Bases and Salts – Class 9 Science Question & Answers (Maharashtra Board)

01

Identify the odd one out and justify.

  • a) chloride, nitrate, hydride, ammonium

    • Answer Ammonium.

    • Justification: Ammonium (NH4+\text{NH}_{4}^{+}) is a positively charged ion (cation), whereas all the others (chloride, nitrate, hydride) are negatively charged ions (anions).

  • b) hydrogen chloride, sodium hydroxide, calcium oxide, ammonia

    • Answer Hydrogen chloride.

    • Justification: Hydrogen chloride (HCl\text{HCl}) is an acid, whereas sodium hydroxide, calcium oxide, and ammonia are basic in nature.

  • c) acetic acid, carbonic acid, hydrochloric acid, nitric acid

    • Answer Acetic acid.

    • Justification: Acetic acid is an organic acid found naturally in living things, while carbonic acid, hydrochloric acid, and nitric acid are inorganic (mineral) acids.

  • d) ammonium chloride, sodium chloride, potassium nitrate, sodium sulphate

Answer Potassium hydroxide (or depending on typical textbook sets, let's check standard variations like ammonium chloride which is acidic salt).

Justification: Ammonium chloride is an acidic salt formed from a strong acid and a weak base, while sodium chloride, potassium nitrate, and sodium sulphate are neutral salts.

02

Write down the changes that will be seen in each instance and explain the reason behind it.

a) 50ml water is added to 50ml solution of copper sulphate.

  • Answer The deep blue color of the copper sulphate solution becomes lighter (pale blue) due to dilution. This is a physical change where the concentration of solute particles per unit volume decreases.

b) A litmus paper was dropped into 2ml dilute HCl. Then 2ml concentrated NaOH was added to it and stirred.

  • Answer When blue litmus paper is dropped into dilute HCl\text{HCl}, it turns red because acids are acidic in nature. When concentrated NaOH\text{NaOH} is subsequently added and stirred, the solution undergoes neutralization, and the litmus paper turns blue as the basic nature takes over once the acid is completely neutralized.

c) Dilute H2SO4\text{H}_{2}\text{SO}_{4} was taken in an electrolytic cell and electric current was passed through it.

  • Answer Bubbles of gas will form at both electrodes. Hydrogen gas evolves at the cathode (negative electrode) and oxygen gas evolves at the anode (positive electrode) because water molecules undergo electrolysis in the presence of the acid.

d) Magnesium oxide was added to dilute HCl and magnesium oxide was added to dilute NaOH.

  • Answer When magnesium oxide (a basic oxide) is added to dilute HCl\text{HCl}, it dissolves and forms magnesium chloride and water through a neutralization reaction. However, when added to dilute NaOH\text{NaOH}, no reaction takes place because both substances are basic in nature and bases do not react with other bases.

e) Zinc oxide was added to dilute HCl and zinc oxide was added to dilute NaOH.

  • Answer Zinc oxide is an amphoteric oxide, meaning it reacts with both acids and bases. When added to dilute HCl\text{HCl}, it forms zinc chloride and water. When added to dilute NaOH\text{NaOH}, it reacts to form sodium zincate and water.
03

Classify the following oxides into three types and name the types.

(CaO, MgO, CO2\text{CO}_{2}, SO3\text{SO}_{3}, Na2O\text{Na}_{2}\text{O}, ZnO, Al2O3\text{Al}_{2}\text{O}_{3}, Fe2O3\text{Fe}_{2}\text{O}_{3})

  • Answer

    • Acidic Oxides: CO2\text{CO}_{2} (Carbon dioxide), SO3\text{SO}_{3} (Sulphur trioxide)

    • Basic Oxides: CaO\text{CaO} (Calcium oxide), MgO\text{MgO} (Magnesium oxide), Na2O\text{Na}_{2}\text{O} (Sodium oxide), Fe2O3\text{Fe}_{2}\text{O}_{3} (Ferric oxide)

    • Amphoteric Oxides: ZnO\text{ZnO} (Zinc oxide), Al2O3\text{Al}_{2}\text{O}_{3} (Aluminium oxide)

04

Explain the following terms.

  • a) Acid: An acid is a substance that dissolves in water to release hydrogen ions (H+\text{H}^{+}) as the only positively charged ions. They have a sour taste and turn blue litmus paper red.

  • b) Base: A base is a substance that can neutralize an acid or accept protons, releasing hydroxide ions (OH−\text{OH}^{-}) when dissolved in water. They have a bitter taste and turn red litmus paper blue.

  • c) Neutralization: A chemical reaction in which an acid and a base react together to form salt and water, effectively nullifying each other's properties.

  • d) Cation: A positively charged ion formed when an atom or molecule loses one or more electrons during ionization or electrolysis.

  • e) Anion: A negatively charged ion formed when an atom or molecule gains one or more electrons.

05

State the differences between:

a) Acids and Bases

  • Acids: Have a pH value less than 77, taste sour, and turn blue litmus red. Example: HCl\text{HCl}.

  • Bases: Have a pH value greater than 77, taste bitter, and turn red litmus blue. Example: NaOH\text{NaOH}.

b) Cation and Anion

  • Cation: Positively charged particle formed by losing electrons; moves towards the cathode during electrolysis.

  • Anion: Negatively charged particle formed by gaining electrons; moves towards the anode during electrolysis.

06

Write down the concentration of the solution in g/L and mol/L if:

a) 7.3 g HCl is present in 100 ml solution

  • Solution:

    • Molecular mass of HCl=1+35.5=36.5 g/mol\text{HCl} = 1 + 35.5 = 36.5\text{~g/mol}.

    • Moles of HCl=7.3÷36.5=0.2 mol\text{HCl} = 7.3 \div 36.5 = 0.2\text{~mol}.

    • Volume in Litres =100 ml=0.1 L= 100\text{~ml} = 0.1\text{~L}.

    • Concentration in g/L=7.3 g÷0.1 L=𝟕𝟑 g/L\text{g/L} = 7.3\text{~g} \div 0.1\text{~L} = \mathbf{73}\text{~g/L}.

    • Concentration in mol/L=0.2 mol÷0.1 L=𝟐 mol/L\text{mol/L} = 0.2\text{~mol} \div 0.1\text{~L} = \mathbf{2}\text{~mol/L}.

b) 2 g NaOH is present in 50 ml solution

  • Solution:

    • Molecular mass of NaOH=23+16+1=40 g/mol\text{NaOH} = 23 + 16 + 1 = 40\text{~g/mol}.

    • Moles =2÷40=0.05 mol= 2 \div 40 = 0.05\text{~mol}.

    • Volume =50 ml=0.05 L= 50\text{~ml} = 0.05\text{~L}.

    • Concentration in g/L=2 g÷0.05 L=𝟒𝟎 g/L\text{g/L} = 2\text{~g} \div 0.05\text{~L} = \mathbf{40}\text{~g/L}.

    • Concentration in mol/L=0.05 mol÷0.05 L=𝟏 mol/L\text{mol/L} = 0.05\text{~mol} \div 0.05\text{~L} = \mathbf{1}\text{~mol/L}.

c) 3 g CH3COOH\text{CH}_{3}\text{COOH} is present in 100 ml solution

  • Solution:

    • Molecular mass of acetic acid =(2×12)+(4×1)+(2×16)=60 g/mol= (2 \times 12) + (4 \times 1) + (2 \times 16) = 60\text{~g/mol}.

    • Moles =3÷60=0.05 mol= 3 \div 60 = 0.05\text{~mol}. Volume =0.1 L= 0.1\text{~L}.

    • Concentration in g/L=3÷0.1=𝟑𝟎 g/L\text{g/L} = 3 \div 0.1 = \mathbf{30}\text{~g/L}.

    • Concentration in mol/L=0.05÷0.1=0.5 mol/L\text{mol/L} = 0.05 \div 0.1 = \mathbf{0.5}\text{~mol/L}.

d) 4.9 g H2SO4\text{H}_{2}\text{SO}_{4} is present in 200 ml solution

  • Solution:

    • Molecular mass of H2SO4=(2×1)+32+(4×16)=98 g/mol\text{H}_{2}\text{SO}_{4} = (2 \times 1) + 32 + (4 \times 16) = 98\text{~g/mol}.

    • Moles =4.9÷98=0.05 mol= 4.9 \div 98 = 0.05\text{~mol}. Volume =0.2 L= 0.2\text{~L}.

    • Concentration in g/L=4.9÷0.2=24.5 g/L\text{g/L} = 4.9 \div 0.2 = \mathbf{24.5}\text{~g/L}.

    • Concentration in mol/L=0.05÷0.2=0.25 mol/L\text{mol/L} = 0.05 \div 0.2 = \mathbf{0.25}\text{~mol/L}.

07

Answer the following questions.

a) Classify the acids according to their basicity and give one example of each type.

  • Answer

    • Monobasic Acids: Produce one hydrogen ion per molecule. Example: Hydrochloric acid (HCl\text{HCl}).

    • Dibasic Acids: Produce two hydrogen ions per molecule. Example: Sulphuric acid (H2SO4\text{H}_{2}\text{SO}_{4}).

    • Tribasic Acids: Produce three hydrogen ions per molecule. Example: Phosphoric acid (H3PO4\text{H}_{3}\text{PO}_{4}).

b) Explain what is meant by electrolysis of water.

  • Answer Electrolysis of water is the process of passing an electric current through acidified water to break it down into its constituent elements: hydrogen gas and oxygen gas. Because pure water is a poor conductor, a small amount of acid or salt is added to help carry the current.

c) Hydronium ions are always in the form H3O+\text{H}_{3}\text{O}^{+}. Give reasons.

  • Answer Free hydrogen ions (H+\text{H}^{+}) are extremely unstable and cannot exist independently in water. Therefore, the moment an acid dissolves in water, the H+\text{H}^{+} ion immediately combines with a neutral water molecule (H2O\text{H}_{2}\text{O}) to form a stable hydronium ion (H3O+\text{H}_{3}\text{O}^{+}).

d) Explain the neutralization reaction with examples and daily life applications.

  • Answer

    • Explanation: Neutralization happens when an acid reacts with a base to produce salt and water. For example, mixing sodium hydroxide and hydrochloric acid yields sodium chloride and water (NaOH+HCl→NaCl+H2O\text{NaOH} + \text{HCl} \rightarrow \text{NaCl} + \text{H}_{2}\text{O}).

    • Daily Life Applications:

      1. Acidity relief: Taking a mild antacid (base) like milk of magnesia to neutralize excess stomach acid during indigestion.

      2. Tooth decay prevention: Toothpastes are basic and neutralize the acids produced by bacteria in our mouth after eating sugary foods.

08

Write the chemical equations for the following activities.

(a) NaOH\text{NaOH} solution was added to HCl\text{HCl} solution.

NaOH(aq)+HCl(aq)→NaCl(aq)+H2O(l)\text{NaOH}_{(aq)} + \text{HCl}_{(aq)} \rightarrow \text{NaCl}_{(aq)} + \text{H}_{2}\text{O}_{(l)}

  • Explanation: When sodium hydroxide (a strong base) mixes with hydrochloric acid (a strong acid), a neutralization reaction occurs, producing common salt (NaCl\text{NaCl}) and water (H2O\text{H}_{2}\text{O}).

(b) Zinc dust was added to dilute H2SO4\text{H}_{2}\text{SO}_{4}.

Zn(s)+H2SO4(aq)→ZnSO4(aq)+H2↑\text{Zn}_{(s)} + \text{H}_{2}\text{SO}_{4}_{(aq)}^{} \rightarrow \text{ZnSO}_{4}_{(aq)}^{} + \text{H}_{2} \uparrow

  • Explanation: An active metal like zinc reacts with dilute sulphuric acid, displacing hydrogen to form a metal salt (zinc sulphate) while releasing bubbles of hydrogen gas.

(c) Dilute nitric acid was added to calcium oxide.

CaO(s)+2HNO3(aq)→Ca(NO3)2(aq)+H2O(l)\text{CaO}_{(s)} + 2\text{HNO}_{3}_{(aq)}^{} \rightarrow \text{Ca(NO}_{3})_{2}_{(aq)}^{} + \text{H}_{2}\text{O}_{(l)}

  • Explanation: Calcium oxide is a basic oxide. When it reacts with dilute nitric acid, it neutralizes the acid to form a soluble salt (calcium nitrate) and water.

(e) Carbon dioxide gas was passed through KOH\text{KOH} solution.

CO2(g)+2KOH(aq)→K2CO3(aq)+H2O(l)\text{CO}_{2}_{(g)}^{} + 2\text{KOH}_{(aq)} \rightarrow \text{K}_{2}\text{CO}_{3}_{(aq)}^{} + \text{H}_{2}\text{O}_{(l)}

  • Explanation: Carbon dioxide acts as an acidic oxide. When bubbled through potassium hydroxide (an alkali), it reacts to form potassium carbonate and water.

(f) Dilute HCl\text{HCl} was poured on baking soda.

NaHCO3(s)+HCl(aq)→NaCl(aq)+H2O(l)+CO2↑\text{NaHCO}_{3}_{(s)}^{} + \text{HCl}_{(aq)} \rightarrow \text{NaCl}_{(aq)} + \text{H}_{2}\text{O}_{(l)} + \text{CO}_{2} \uparrow

  • Explanation: Baking soda (sodium hydrogen carbonate) reacts vigorously with hydrochloric acid, producing sodium chloride, water, and rapid effervescence due to the release of carbon dioxide gas.
09

State the differences.

a. Acids and bases

  • Acids: Taste sour, have a pH below 77, turn blue litmus paper red, and release H+\text{H}^{+} ions in water. Example: HCl\text{HCl}.

  • Bases: Taste bitter, have a pH above 77, turn red litmus paper blue, and release OH−\text{OH}^{-} ions in water. Example: NaOH\text{NaOH}.

b. Cation and anion

  • Cation: A positively charged ion formed by losing electrons; it moves towards the cathode (negative electrode) during electrolysis. Example: Na+\text{Na}^{+}.

  • Anion: A negatively charged ion formed by gaining electrons; it moves towards the anode (positive electrode) during electrolysis. Example: Cl−\text{Cl}^{-}.

c. Name the electrodes shown in the figure and explain them.

Electrolysis diagram showing negative electrode (cathode) and positive electrode (anode) with cations and anions - Class 9 Acids Bases and Salts

Electrolysis: movement of ions towards electrodes

  • Negative electrode (Cathode): Connected to the negative terminal of a power source; attracts positively charged cations and is the site where reduction (gain of electrons) takes place.

  • Positive electrode (Anode): Connected to the positive terminal of a power source; attracts negatively charged anions and is the site where oxidation (loss of electrons) takes place.

10

Classify aqueous solutions of the following substances according to their pH into three groups : 7, more than 7, less than 7.

(Substances: Common salt, sodium acetate, hydrochloric acid, carbon dioxide, potassium bromide, calcium hydroxide, ammonium chloride, vinegar, sodium carbonate, ammonia, sulphur dioxide)

  • Answer Grouped by pH:

    • Group 1: pH equal to 7 (Neutral Solutions)

      • Common salt (NaCl\text{NaCl}) and Potassium bromide (KBr\text{KBr})

      • Reason: They are salts formed from a strong acid and a strong base, making their aqueous solutions neutral.

    • Group 2: pH more than 7 (Basic / Alkaline Solutions)

      • Sodium acetate (CH3COONa\text{CH}_{3}\text{COONa}), Calcium hydroxide (Ca(OH)2\text{Ca(OH)}_{2}), Sodium carbonate (Na2CO3\text{Na}_{2}\text{CO}_{3}), and Ammonia (NH3\text{NH}_{3})

      • Reason: They either release hydroxide ions directly or form alkaline solutions due to basic properties or hydrolysis (salts of weak acids and strong bases).

    • Group 3: pH less than 7 (Acidic Solutions)

      • Hydrochloric acid (HCl\text{HCl}), Carbon dioxide (CO2\text{CO}_{2} - forms carbonic acid in water), Ammonium chloride (NH4Cl\text{NH}_{4}\text{Cl} - acidic salt), Vinegar (acetic acid), and Sulphur dioxide (SO2\text{SO}_{2} - forms sulphurous acid in water)

      • Reason: They release hydronium/hydrogen ions in water, causing the solution to become acidic.

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